What is the voltage drop for a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors?

To determine the voltage drop in a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors, we can use the voltage drop formula:

Voltage Drop (V) = 2 x Length (feet) x Current (Amps) x Resistivity (Ohms per foot)

For copper conductors, the resistivity at room temperature is approximately 0.001588 Ohms per foot for 8 AWG wire.

Here’s how the calculation unfolds:

1. Calculate the distance in one direction: Since the circuit includes both the outgoing and return path, you double the length, which gives us 640 feet.

2. Insert the values into the formula:

• Length = 640 feet (total round trip distance)

• Current = 32 Amps

• Resistivity for 8 AWG copper = 0.001588 Ohms/foot

3. Calculate the voltage drop:

[

Voltage Drop = 2 x 320 \text{ feet} x 32 \text{ Amps} x 0.001588 \text{ Ohms/foot}

]

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Voltage Drop